Determine the equation of the line in the following graph:
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Let A ( x1 , y1 ) = ( -4 , 2 ) ,
B( x2 , y2 ) = ( 12 , -3 )
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We know the ,
Equation of a line joining the points
A( x1 , y1 ) and B( x2 , y2 ) is
( y - y1 )( x2 - x1 ) = ( y2 - y1 )( x - x1 )
*****************************************
Now ,
Equation of a line AB is
( y - 2 )[ 12 - ( -4) ] = ( -3 - 2 )[ x - 2 ]
=> ( y - 2 )( 12 + 4 ) = (-5)( x -2 )
=>( y - 2 )16 = -5x + 10
=> 16y - 32 = -5x + 10
=> 5x + 16y = 10 + 32
=> 5x + 16y = 42
Therefore ,
Required equation of the line ,
5x + 16y = 42
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B( x2 , y2 ) = ( 12 , -3 )
**************************************
We know the ,
Equation of a line joining the points
A( x1 , y1 ) and B( x2 , y2 ) is
( y - y1 )( x2 - x1 ) = ( y2 - y1 )( x - x1 )
*****************************************
Now ,
Equation of a line AB is
( y - 2 )[ 12 - ( -4) ] = ( -3 - 2 )[ x - 2 ]
=> ( y - 2 )( 12 + 4 ) = (-5)( x -2 )
=>( y - 2 )16 = -5x + 10
=> 16y - 32 = -5x + 10
=> 5x + 16y = 10 + 32
=> 5x + 16y = 42
Therefore ,
Required equation of the line ,
5x + 16y = 42
•••••
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