Determine the equation of the line which passes through the points (0,−8) and (7,0).
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Answered by
5
Hi Mate!!!
Equation of line passing through the point ( x1 , y1 ) and having slope m is
y - y1 = m ( x - x1 )
y1 = -8 x1 = 0 and m = 0 + 8 / 7 + 0 = 8 / 7
y +8 = 8 / 7 ( x - 0 )
7y - 8x + 56 = 0
Have a nice time.
Equation of line passing through the point ( x1 , y1 ) and having slope m is
y - y1 = m ( x - x1 )
y1 = -8 x1 = 0 and m = 0 + 8 / 7 + 0 = 8 / 7
y +8 = 8 / 7 ( x - 0 )
7y - 8x + 56 = 0
Have a nice time.
Answered by
3
Answer:
8x -7y -56 = 0
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Step-by-step explanation:
y = mx + c
m = (y2-y1)/(x2-x1)
m = (0-(-8))/(7-0)
m = 8/7
x = 7 , y= 0
0 = (8/7)*7. + c
c = -8
y = (8/7)x -8
7y = 8x - 56
8x -7y -56 = 0
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