determine the equation of the straight line passing through the point [-1,-2] and having slope 4/7-yahoo answers
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so we know m = tanθ = slope
m = (y - y₁)/(x - x₁)
4/7 = (y + 2)/(x + 1)
⇒ 4x + 4 = 7y + 14
⇒4x - 7y - 10 = 0 is the equation of the given line
m = (y - y₁)/(x - x₁)
4/7 = (y + 2)/(x + 1)
⇒ 4x + 4 = 7y + 14
⇒4x - 7y - 10 = 0 is the equation of the given line
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