Determine the equivalent capacitance between A and B in the network shown.
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Explanation:
Because C1,C2 and C3 are in series :
1/C'=1/C1+1/C2+1/C3
1/C'=3/1
C'=1/3
Because C'and C4 are in parallel:
So equivalent capacitance C:
C=C4+C'
C=1/3+2=7/3Mf
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