Determine the equivalent resistance of series and parallel combination of resistance?
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- To find the equivalent resistance of the circuit, notice that the parallel connection of R2 and R3 is in series with R1, so the equivalent resistance is Req=R1+(1R2+1R3)−1=1.00Ω+(16.00Ω+113.00Ω)−1=5.10Ω. ...
- The current through R1 is equal to the current supplied by the battery: I1=I=VReq=12.0V5.10Ω=2.35A.
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Answer:
- To find the equivalent resistance of the circuit, notice that the parallel connection of R2 and R3 is in series with R1, so the equivalent resistance is Req=R1+(1R2+1R3)−1=1.00Ω+(16.00Ω+113.00Ω)−1=5.10Ω. ...
- The current through R1 is equal to the current supplied by the battery: I1=I=VReq=12.0V5.10Ω=2.35A.
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