Question

determine the final temperature of a mixture of 50 grams of water at 10 degrees C added to 120 grams of water at 80 degrees C

Answer 1

Answer:

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Answer 2

Answer:

59.41 °C

Explanation:

FINAL TEMPERATURE OF MIXTURE IS OBTAINED WHEN EQUILIBRIUM IS ACHIVED.

LET, FINAL TEMPERATURE OF WATER BE "T".

THAT MEANS,

  ⇒ LOSS OF HEAT BY HOT WATER=GAIN OF HEAT BY COLD WATER

 ⇒  (50 gm)*c*(T-10)   =   (120 gm)*c*(80-T)

        WHERE, "c" is the specific heat capacity of water.

⇒   50T - 500 =  9600 - 120T

⇒    T = 59.41 °C