Question

determine the following integral integration X square + 4 x + 8 DX​

Answer 1

Answer:

$\frac{1}{3}$$x^{3\\}$ + 2$x^{2}$ + 8x

Step-by-step explanation:

add one to all the power of all the x's ( imagine 8 is actually 8$x^{0$)

then ivide all multipliers by new index

Answer 2

${\large{\bold{\sf{∫(x²+4x+8).dx}}}}$

${\large{\bold{\sf{=∫x².dx+∫4x.dx+∫8.dx}}}}$

$\large{=}$ ${\large{\bold{\sf{∫\frac{x³}{3}+(4)\frac{x²}{2}+x+c}}}}$

$\large{=}$ ${\large{\boxed{\red{\sf{∫\frac{x³}{3}+2x²+x+c}}}}}$