determine the following polynomial has x+1 as a factor
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x+1 is not the factor of given polynomial
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x + 1 = 0
x = -1
x³ - x² - ( 3 - √3 )x + √3
Putiing value of x = -1 in the equation
(-1)³ - (-1)² - (3 - √3)(-1) + √3
-1 - 1 + 3 +√3 + √3
1 + 2√3
Given equation when expressed as factor of then we get 1 + 2√3
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