Question

determine the following polynomial has X + 1 is a factor of x cube minus 6 square minus 3 minus root 3 X + root 3



plz help me it's important ​

Answer 1

Answer:

x+1 is not factor of p(x)

Step-by-step explanation:

p(x) = x³ - 6x² - (3 - √3)x + √3

x + 1 = 0

x = -1

put x in p(x)

p(-1)= (-1)³ - 6(-1)² - (3 - √3)(-1) + √3

= -1 - 6(1) + (3 - √3) + 3

= -1 - 6 + 3 - √3 + √3

= -7 + 3

= -4

p(-1) ≠ 0

so, x + 1 is not factor of p(x)