Question

Determine the force applied tangentially to a bar

of a screw-jack at a radius of 60 cm, if the torque

required is 750 N m.​

Answer 1

Answer:

Given: m = 8 t = 8000 kg ; k = 0.6 m ; N = 1800 r.p.m. or ω = 2π× 1800/60= ... therefore the force applied on the lever of a screw jack may be considered to be ... Frictional force acting on the ring tangentially at radius r.

Explanation:

mark as brainliest plz