Question

 Determine the force magnitude P  required  to lift one end of the 250-kg crate with the lever dolly as shown. State any assumptions.​

Answer 1

The for magnitude (P) = 224.8125 N

Step-by-step explanation:

According to figure we can observe the the box is stood on only 2 corners of the box

weight on one corner  of the box = $\frac{250}{2}$ kg

Take moment  of the box is 0

gravity of earth(g) = 9.81

length of the lever = 1500mm

distance between wheel & corner(A) = 275mm

m = mass

P × 1500 =  $\frac{mg}{2}$ × 275

P =  $\frac{250}{2}$ × $\frac{9.81}{1500}$  × 275

P = 224.8125 N

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Answer 2

Answer:

Step-by-step explanation: