Physics, asked by tanyabansal849, 2 months ago

Determine the force magnitude P required to lift one end of the 250-kg crate with the lever dolly as
shown. State any assumptions.

Answers

Answered by shivakumar0820
1

Answer:

Explanation:

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Answered by ramansaini1018
0

The for magnitude (P) = 224.8125 N

Step-by-step explanation:

According to figure we can observe the the box is stood on only 2 corners of the box

weight on one corner of the box = 250/2 kg

Take moment of the box is 0

gravity of earth(g) = 9.81

length of the lever = 1500mm

distance between wheel & corner(A) = 275mm

m = mass

P × 1500 = Mg/2× 275

P = 250/2×9.81/1500× 275

P = 224.8125 N

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