Question

Determine the force of gravitational attraction between the earth (m = 5.98 x 1024 kg) and a 70-kg physics student if the student is standing at sea level, a distance of 6.38 x 106 m from earth's center.​

Answer 1

Answer:

The force of gravitational attraction between the earth and the student is 686 N.

Explanation:

From the universal law of gravitation,

F = G Mm / d²

G is the universal gravitational constant, M and m are the masses of the bodies whose force of gravitation is to be found and d is the distance of separation between the bodies.

We have,

Universal gravitational constant, G = 6.67 × 10⁻¹¹ Nm²/Kg²

Mass of the earth, M = 5.98 × 10²⁴ Kg

Mass of the student, m = 70 Kg

Distance of separation, d = 6.38 × 10⁶ m

∴ F = (6.67 × 10⁻¹¹ × 5.98 × 10²⁴ × 70) / (6.38 × 10⁶)²

  F = (2792.062 × 10¹³) / (40.7044 × 10¹²)

  F = 686 N