Question

Determine the force on the input piston used to lift this car. Area=0.005m2 the car is 16000 N and the lifting up is 0.4 m
Pls make it simple Im in grade 8

Answer 1

When a force is applied to a contained, in compressible fluid, the pressure increases equally in all directions throughout the fluid. This fundamental characteristic of fluids provides the foundation for hydraulic systems found in barbershop chairs, construction equipment, and the brakes in your car.

Pascal's Principle

Because the force applied to the contained fluid is distributed throughout the system, you can multiply the applied force through this application of Pascal’s Principle in the following manner. Assume you have a closed container filled with an in compressible fluid with two pistons of differing areas, A1 and A2. If you apply a force, F1, to the piston of area A1, you create a pressure in the fluid which you can call P1.

Pressure Formula

Similarly, the pressure at the second piston, P2, must be equal to F2 divided by the area of the second piston, A2.

Pressure Formula for P2

Since the pressure is transmitted equally throughout the fluid in all directions according to Pascal’s Principle, P1 must equal P2.

Force Multiplier 2

Rearranging to solve for F2, you find that F2 is increased by the ratio of the areas A2 over A1.

Force Multiplier 1

Therefore, you have effectively increased the applied force F1. Of course, the law of conservation of energy cannot be violated, so the work done on the system must balance the work done by the system. In the hydraulic lift diagram shown on the previous page, the distance over which F1 is applied will be greater than the distance over which F2 is applied, by the exact same ratio as the force multiplier!

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Answer 2

Answer:

Force to be applied as input = 200Newtons

Explanation:

By the procedure of Hydraulic lift system, we know that:

F1/A1 = F2/A2 --(i)

Where,

'F1' and 'A1' are the force and area of the first piston,

'F2' and 'A2' are the force and area of the second piston,

Now, we are given;

Force exerted on the piston lifting the car = F1 = 16000N,

Area of the piston lifting the car = A1 = 0.4m²

Area of the piston at which input force is applied = A2 = 0 005m²

Force ro be exerted as input = F2 = ?

Thus, putting the values in eq(i):

16000/0.4 = F2/0.005

Thus,

F2 = (16000/0.4)×0.005

Therefore,

F2 = 200Newtons.