Question

determine the forceper unit/area required to compress the volume of water by one percent. bulk modulus of water is 2*10^10 dynes/cm^2​

Answer 1

Answer:

This ratio is very high because air is much more compressible than water.

Explanation:

Initial volume, V

1

=100.0l=100.0×10

−3

m

3

Final volume, V

2

=100.5l=100.5×10

−3

m

3

Increase in volume, V=V

2

−V

1

=0.5×10

−3

m

3

Increase in pressure, p=100.0atm=100×1.013×10

5

Pa

Bulk modulus = p/(ΔV/V

1

)=pV

1

/ΔV

= 100×1.013×10

5

×100×10

−3

/(0.5×10

−3

)

= 2.026×10

9

Pa

Bulk modulus of air = 1×10

5

Pa

Bulk modulus of water / Bulk modulus of air = 2.026×10

9

/(1×10

5

)=2.026×10

4

This ratio is very high because air is much more compressible than water.