determine the frequency x question 28
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Answer:
x=8
Step-by-step explanation:
As the mode is 67, which lies b/w 60-70, we assume the highest frequency to be 15
Mode= l+(f1-f0/2f1-f2-f0)×h
Where,
l= lower limit of f1=60
h= class mark=10
f1=highest frequency=15
f2=succeeding frequency=12
f0=preceding frequency=x
Replacing values, we get,
60+(15-x/30-12-x)×10= 67
(15-x/18-x)10=7
150-10x=126-7x
150-126=(10-7)x
3x=24
x=8
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