Determine the greatest 3-digit number exactly divisible by 6,10&12
Answers
Answered by
0
Answer:
2
Step-by-step explanation:
here we have to find hcf of given number
2|6. 2|10. 2 | 12.
3|3. 5|5. 2 | 6.
|1. | 1. 3 | 3.
| 1.
HCF of 6,10 and 12 are
given
6 => 2 × 3
10 => 2 × 5
12 => 2 × 2 × 3
the common number is 2, so the least number by which it is divisible is 2
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Answered by
0
Answer:
960
Step-by-step explanation:
LCM of 6,10 and 12 is 60.
Now multiply 60 by such a number that the answer would be the greatest 3 digit number i.e.,60×16=960 which is the greatest 3 digit number exactly divisible by 6,10 and 12.
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