determine the greatest 5 digit number which is exactly divisible by each of 8,15and 21
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By investigating the prime factorizations of 8 (2x2x2), 15 (3x5), and 21 (3x7), you can determine that their Least Common Multiple is 2x2x2x3x5x7 which is 840. The greatest 5 digit number is 99999. When you divide that by 840, you get 119 and a remainder. So your answer is 840x119 = 99960.
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