Determine the greatest3-digit number exactly divisible by 8 10 12
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Answer:
Lowest common multiple of 8,10 and 12 is 120. Now divide greatest 3 digit number 999 by 120. And subtract the remainder you get by dividing 999 by 120. The result that you get is greatest 3 digit number divisible by 8,10,12.
Step-by-step explanation:
999=120×8+39
So the remainder is 39.
And the number is
999-39=960 Answer
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⛦ⓈⓄⓁⓊⓉⒾⓄⓃ⛦
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❤...ʟᴏᴡᴇsᴛ ᴄᴏᴍᴍᴏɴ ᴍᴜʟᴛɪᴘʟᴇ ᴏғ 8, 10 ᴀɴᴅ 12 ɪs 120.
ɴᴏᴡ ᴅɪᴠɪᴅᴇ ᴛʜᴇ ɢʀᴇᴀᴛᴇsᴛ ᴛʜʀᴇᴇ ᴅɪɢɪᴛ ɴᴜᴍʙᴇʀ 999 ʙʏ 120.
ᴀɴᴅ sᴜʙᴛʀᴀᴄᴛ ᴛʜᴇ ʀᴇᴍᴀɪɴᴅᴇʀ ʏᴏᴜ ɢᴇᴛ ғᴏʀᴍ 999.
ᴛʜᴇ ʀᴇsᴜʟᴛ ᴛʜᴀᴛ ʏᴏᴜ ɢᴇᴛ ɪs ɢʀᴇᴀᴛᴇsᴛ 3-ᴅɪɢɪᴛ ɴᴜᴍʙᴇʀ ᴅɪᴠɪsɪʙʟᴇ ʙʏ 8, 10 ᴀɴᴅ 12. ɪ.ᴇ; 999 = 120×8+39,
sᴏ, 39 ɪs ᴛʜᴇ ʀᴇᴍᴀɪɴᴅᴇʀ.
ᴀɴᴅ ᴛʜᴇ ɴᴜᴍʙᴇʀ ɪs 999-39= 960...❤
So, 960 is the greatest three digit number divisible by 8, 10 and 12.
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ᴾᴸᶻ ᴹᴬᴿᴷ ᴬˢ ᴮᴿᴬᴵᴺᴸᴵᴱˢᵀ ᴰᴱᴬᴿ✔♥
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