Question

Determine the HCF of following pairs by finding factors
1. 16 and 48
2. 14 and 28
3. 4 and 6
4. 18 and 36


please give me correct answer please​

Answer 1

Answer:

1. 2×2×2×2×3= 48

2. 2×2×7= 28

3. 2×2×3= 12

4. 2×2×3×3= 36

Answer 2

Answer:

16 = 2x2x2x2

48= 2x2x2x2x3

therefore highest common factor is 2x2x2x2 = 16

1. 14 = 2x7

28= 2x2x7

therefore hcf is 2x7 = 14

4= 2x2

6= 2x3

therefore hcf = 2

18 = 2x3x3

36 = 2x2x3x3

therefore hcf = 2x3x3 = 18

Step-by-step explanation:

all of these are correct answer

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