Determine the HCF of the following by prime factorisation:
(ii) 289, 391
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2
Answer:
17
Step-by-step explanation:
289 = 17^2
391 = 17 × 23
Multiply all the common prime factors, by the lowest exponents.
Greatest (highest) common factor (divisor):
HFC :(289; 391) = 17
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