Question

determine the hybridisation of oxygen in H30+

Answer 1

Answer:

☆. Four sp3 hybrid orbitals on the oxygen atom. Because in H3O+ , O has three bond pairs and one lone pair.

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Answer 2

Answer:

SP3 Hybridization .

Explanation:

When we talk about hybridization , let suppose H3O+ as mentioned in the question.

We will consider the central atom of the molecule for Hybridization.

In this case we have Oxygen atom as central atom, so only Oxygen will undergo Hybridization.

Hydrogen is not going to Hybridize.

Now, Lets discuss the type of hybridization in this case.

We have four groups on our central atom( O ) :

3 Hydrogen atoms

1 Lone pair of electron

Simple way to understand the number of hybrid orbitals that we need , is to find out , how much groups are attached to the central atom ,

Once we know the number of attached groups , Here is simple rule to apply

1 Group = s1 Hybridization

2 groups = s1p1 Hybridization

3 groups = s1p2 Hybridization

4 groups = s1p3 Hybridization

5 groups =s1p3d1 Hybridization

6 groups =s1p3d2 Hybridization

In this case we have four groups attached to central atom , so central atom will undergo simply SP3 Hybridization .

Somehow if still we ask about Hydrogen, so looking at the table Hydrogen has one group( O atom) attached to it , so it will give S1 Hybridization , which will be the same orbital as that if it was un-hybridized .

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