Determine the image distance and image height for a 5.00-cm tall object placed 30.0 cm from a concave mirror having a focal length of 15.0 cm.pls answer breifly
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0
Answer:
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Answered by
2
Answer:
1.65
Step-by-step explanation:
given,
object distance u = -30
focal length ,f = 15 cm
ATF ,
1/v+1/u = 1/f
1/v= 1/f = 1/u
1/v = 1/15 -(-1/30)
1/v = 1/15 +1/30
v = 30/3= 10 cm
therefore , distance of the image is 10 cm
now , -v/u = h'/h
h'----> height of the image
h-----> height of the object i.e 5
therefore -10/-30 = h'/5
h' =5/3 =1.67 cm
hence , image height = 1.67
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