Question

Determine the inclination of resultant of

force 100N at 0° and 200N at 90°.​

Answer 1

Answer:

63.43 degree

Explanation:

Answer 2

Given:

Two Force vectors,

F $_1$$=100N$ inclined at $0$°

F $_2$$=200N$ inclined at $90$°

To FInd:

The inclination of resultant of two forces.

Solution:

When two vectors A and B are added, the angle $\beta$ made by their resultant R with A is given by

         $\beta =tan^{-1}(\frac{Bsin\alpha }{A+Bcos\alpha } )$

where $\alpha$ is the angle between the vectors.

Substituting the given values of the vectors and the angle in the formula we get,

        $\beta =tan^{-1}(\frac{200sin90^o }{100+200cos90^0 } )$

   ⇒ $\beta =tan^{-1}(2)=63.43^0$

Hence, the resultant of the two forces is inclined at an angle of 63.43°.