Question

Determine the inclination of resultant of

force 100N at 0° and 200N at 90°.
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Answer 1

Explanation:

1.) 100N at 0° that is cos0 = 1

so the answer will be = 100*1 = 100N

2.) 200N at 90° that is cos90 = 0

so the answer will be = 200*0 = 0N

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Answer 2

The inclination of the resultant force of 100N at 0° and 200N at 90° will be 63.43°

Given forces are

F1 = 100 N at 0°  inclination

F2 = 200 N at 90°  inclination

We can see that these forces are perpendicular to each other, therefore the resultant force will be equal to

Fnet = $\sqrt{F1^2 + F2^2}$

Fnet = $\sqrt{100^2 + 200^2}$

Fnet = 223.606 N

Now to find the inclination of this net force we will use the formula

tanФ = $\frac{Fy}{Fx}$

here Fy = 200 N and Fx = 100 N

tanФ = 2

Ф = 63.43°

Therefore, the inclination of the resultant force will be 63.43°.