Determine the ink of the ABC quadrilateral in the figure
from the picture.
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angle A =90° so angleC=90°
in triangle dbc
(db)^2=(cb)^2+(dc)^2
db^2=8^2+17^2
db^2=353
db=√353
db=18.7cm
in triangle adb
(db)^2=da^2+ab^2
(18)^2=9^2+ab^2
324-81=ab^2
243=ab^2
ab=√243
ab=15.58 cm
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