Question

Determine the integer whose product with (-1) is (-220)

Answer 1

Answer:

Brainiest me

Step-by-step explanation:

n^2-15n-27=n(n-15)-27

We know that product will be positive as n is a positive integer.

So,

n(n-15)-27>0 or =0

n can't be 3 digit number because the greatest 3 digit number is 999 and if we multiply its digits then we get 9×9×9=729

But n(n-15)-27 >729{always}

So n will be any 2 digit number.

Now, the largest 2 digits no.=99

So maximum product =9×9=81

So,

n(n-15)-27<81 or =81

Or,n(n-15)<81 +27

Or,n(n-15)<108 or=108

Or,n<20 or=20

Also,n>15 because if it will be less than 15 then the product will be negative.

So,n can be 16,17,18 ,19

Now, if n=16 then n(n-15)-27=16×1-27=-11[not possible]

If n=17,then n(n-15)-27=17×2-27=34-27=7=1×7[possible]

If n=18,then n(n-15)-27=18×3-27=27 not equal to 1×8 so [not possible]

If n=19,then n(n-15)-27=19×4-27=49 is not equal to 1×9 [not possible]

So, only possible no.=17

So answer =17