Question

Determine the integer whose product with (-1) is (-32) ?​

Answer 1

Step-by-step explanation:

Before getting into the answer, Remember these :

(1) Negative(-) times(x) Negative (-) = positive (+)

(2) Positive(+) times(x) Positive(+) = positive(+)

(3) Negative(-) times(x) Positive(+) = negative(-)

Now, The answer :

(a) The result should be -22,

We have -1,

To get negative from negative, We must multiply positive,

Now take out the signs, And think how much should be multiplied to 1, To get 22,

It's +22,

So the answer is +22,

(b) Result should be +37,

We have -1,

We need to get positive from negative, So we need to multiply negative,

=> Take out the signs and think how much should be multiplied to get 37 from 1,

It's 37,

So the answer is -37,

(c) ±0, Anything * 0 is 0, Except infinity,

=> -1 Should be Multiplied with 0, To get 0,

=> The answer is 0,

Therefore : The answers are :

(a) +22

(b) -37

(c) 0,

Hope you understand, Have a Great day :D,

Answer 2

Answer:

Concept - Sign Rules

Given - Number is -1 and -32

Find - Determine the integer whose product with (-1) is (-32)

Step-by-step explanation:

As we know that

Negative(-) times(x) Negative (-) = positive (+)

Positive(+) times(x) Positive(+) = positive(+)

Negative(-) times(x) Positive(+) = negative(-)

let X be that integer

So by applying this concept we get

X = -32 * -1

X =  32

Hence the solution is 32

#SPJ2