determine the integral of 2x^3-7x+2/(x-1)^2 to the respect of function x
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I am going to use %sign for integral. Hope you'd understand it.
=%(2x^3)-%(7x)+%2/(x-1)^2
=2%x^3-7%x+2%1/(x-1)^2
=2(x^4/4)-7(x^2/2)+2[(x-1)^-3]/-3
=(x^4/2) - 7(x^2)/2 - 2/3(x-1)^3
sumanduttamotog4:
please give me answer
=2%x^3dx - 7%xdx +2%dx/(x^3+2x)
ok
=(x^4)/2 - 7(x^2)/2 + 2ln(x^3+2x^2)
you can ask me if you don't understand any line
Maths practice se hi ata ha
A lot of thanks
god bless you
My pleasure ❤️
God bless you and your family too.
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