Math, asked by leekhalakshita, 5 hours ago

determine the largest 4 digit number divisible by 12,15 and 18

Answers

Answered by AditiKH
0

Answer:

The largest number of four digits is 9999.

Required number must be divisible by L.C.M of 12,15,18i.e., 540.

On dividing 9999 by 540, we get 279 as remainder.

∴ Required number=(9999−279)=9720.

Step-by-step explanation:

Hope it helps!

Answered by suryanshsingh020
0

Answer:

Answer:

The largest number of four digits is 9999.

Required number must be divisible by L.C.M of 12,15,18i.e., 540.

On dividing 9999 by 540, we get 279 as remainder.

∴ Required number=(9999−279)=9720.

Step-by-step explanation:

Hope it helps!

Step-by-step explanation:

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