determine the largest 4 digit number divisible by 12,15 and 18
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Answered by
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Answer:
The largest number of four digits is 9999.
Required number must be divisible by L.C.M of 12,15,18i.e., 540.
On dividing 9999 by 540, we get 279 as remainder.
∴ Required number=(9999−279)=9720.
Step-by-step explanation:
Hope it helps!
Answered by
0
Answer:
Answer:
The largest number of four digits is 9999.
Required number must be divisible by L.C.M of 12,15,18i.e., 540.
On dividing 9999 by 540, we get 279 as remainder.
∴ Required number=(9999−279)=9720.
Step-by-step explanation:
Hope it helps!
Step-by-step explanation:
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