Determine the least number which when divided by 3, 4 and 5 leaves remainder 2 in each case.
Answers
Answered by
227
Leaves remainder 2 when multiplied by 3, 4, 5.
LCM of 3, 4, 5 is 3x4x5 = 60
60 + 2 = 62
Therefore, the required number is 62
LCM of 3, 4, 5 is 3x4x5 = 60
60 + 2 = 62
Therefore, the required number is 62
Answered by
86
Answer :
62 is the least number which when divide by 5, 4 and 3 then leave remainder 2.
Step by step explanation :
Hey Mate,
To find the least number which when divide by 5, 4 and 3 then leave remainder 2.
So, we have to calculate the L.C.M of the 5, 4, 3.
L.C.M of 5, 4 and 3 are 60.
Now, Just add 2 in 60.
So, 60 + 2 = 2.
62 is the least number which when divide by 5, 4 and 3 then leave remainder 2.
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