Question

determine the least number which when divided by
4 ,5, 6 and leaves remainder 3 in each cage​

Answer 1

Answer:

==》57

☆ Here, 4 – 1 = 3, 5 – 2 = 3, 6 – 3 = 3

☆ ∴ The required Number = LCM of (4, 5, 6) – 3

= 60 – 3 = 57.