Question

Determine the least number which when divided by 44, 62, 82 and 102 leaves a remainder 4 in each case.​

Answer 1

Answer:

If you want a number which is divisible by 24 & 36 by at least 1, then 72 is the smallest number which is divisible by both 24 & 36 and have the same remainder (that is 0). If the remainder is non zero then 73 is the number required.

Step-by-step explanation:

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Answer 2

Answer:

2852128

Step-by-step explanation:

LCM of 44, 62, 82 and 102 = 2852124

since, remainder is 4,

so, reqd. number = 2852124 + 4 = 2852128

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