Math, asked by kanha50741, 11 months ago

Determine the least three digit number which when divided by 3, 4 and 5 leaves remainder 2 in each case.

Answers

Answered by abhinavtiwari36
3

Step-by-step explanation:

let no. be y,

now as it leaves remainder 2 in each case then y-2 will definitely divide by all of them 3,5 ,4

(y-2)/3=k,(y-2)/4=l,(y-2)/5=m

y-2=3k=4l=5m

talking lcm of

3,4,5 is 60 so first no. is y-2=60=>y=62 but it is 2 digital no.

next common multiple of 3,4,5 is 120

y-2=120

=>y=122

Answered by Anonymous
0

Answer:

62

Step-by-step explanation:

Hey Mate,To find the least number which when divide by 5, 4 and 3 then leave remainder 2.So, we have to calculate the L.C.M of the 5, 4, 3.L.C.M of 5, 4 and 3 are 60.Now, Just add 2 in 60.So, 60 + 2 = 2.62 is the least number which when divide by 5, 4 and 3 then leave remainder 2.

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