Determine the least three digit number which when divided by 3, 4 and 5 leaves remainder 2 in each case.
Answers
Answered by
3
Step-by-step explanation:
let no. be y,
now as it leaves remainder 2 in each case then y-2 will definitely divide by all of them 3,5 ,4
(y-2)/3=k,(y-2)/4=l,(y-2)/5=m
y-2=3k=4l=5m
talking lcm of
3,4,5 is 60 so first no. is y-2=60=>y=62 but it is 2 digital no.
next common multiple of 3,4,5 is 120
y-2=120
=>y=122
Answered by
0
Answer:
62
Step-by-step explanation:
Hey Mate,To find the least number which when divide by 5, 4 and 3 then leave remainder 2.So, we have to calculate the L.C.M of the 5, 4, 3.L.C.M of 5, 4 and 3 are 60.Now, Just add 2 in 60.So, 60 + 2 = 2.62 is the least number which when divide by 5, 4 and 3 then leave remainder 2.
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