determine the length of a chord which is a distance of the circle of the radius 13 cm
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24cm
Step-by-step explanation:
The correct Question is
determine the length of a chord, which is at distance of 5cm from the centre of the circle and the circle is of the radius 13 cm.
Given,
A circle with centre O and Radius = 13cm
also it has a chord 5cm away from the centre
Now, let join OA and OB and draw a perpendicular to the chord AB from the centre O
so, AD = DB
also, OA = OB = 13cm (Radii of the same circle)
and OD = 5cm (away from the centre)
AB = AD + DB
Using pythagoras theorem we get
OD² + DB² = OB²
DB² = OB² - OD²
DB² = 13² - 5² = 169 - 25 = 144
DB = √144 = 12cm
AB = AD + DB
AB = (DB) + DB (because AD = DB)
AB = 2 × DB
AB = 2 × 12 = 24cm
So the length of the chord AB = 24cm
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