determine the length of a chord which is at a distance of 5cm from the centre of the circle of radius 13cm
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Consider Length of Chord be 2x
Let O is the centre of the circle, AB is the chord and D is the point where perpendicular from the centre (OD) intersects the chord AB. Join AO which is the radius of circle.
So,
AO = 13 cm
OD = 5 cm
We know that Perpendicular Distance from the centre bisects the chord.
So AD = x
Now in right triangle ADO
AO² = AD² + OD²
13² = x² + 5²
x² = 169 - 25
x² = 144
x = 12
∴AD = 12 cm
∵ Length of Chord AB = 2AD
∴AB = 24 cm
Hence length of chord is 24 cm
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