Determine the length of the altitude AD of an isosceles triangle abc in which ab=ac= 2a CM and bc=a CM
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In isosceles ∆ ABC, we have:
AB = AC = 2a units and BC = a units
Let AD be the altitude drawn from A that meets BC at D.
Then, D is the midpoint of BC.
BD = BC = a/2 units Applying Pythagoras theorem in right-angled ∆ABD, we have:
Step-by-step explanation:
pythagoras theorem is in image checkout
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