Question

Determine the local Maxima and mima value of 2x3-5x2-36+18

Answer 1

diffrnetiating it we get,

6x^2 - 10x

let dy/dx = 0

then, 6x^2 - 10x = 0

2x(3x-5) = 0

x = 0 or x = 5/3

thus local maxima & minuma is on 0 or 5/3