Question

Determine the location and values of the absolute maximum and obsolute minimum for the given function
f(x)=(-x+2)^4
where p<= X<= 3​

Answer 1

Answer:

f(x)=x³

Therefore, f′(x)=3x²

Now, f′(x)=0⟹x=0

Then, we evaluate the value of f at critical point x=0 and at the end points of the interval [-2,2].

f(0)=0

f(−2)=−8

f(2)=8

Hence, absolute maximum value of f on [-2,2] is 8 occurring at x = 2 and absolute minimum value of f on [-2,2] is -8 occurring x = -2

Hope it helps you