Question

Determine the lowest number which when divided by 16, 28 , 40 , 77 leaves remainder 8 in each case.

Answer 1

Step-by-step explanation:

The least number which when divided by 16,28,40 and 77 leaves 5 as a remainder in each case is 6165.

Step-by-step explanation:

To find : The least number which when divided by 16,28,40 and 77 leaves 5 as a remainder in each case?

Solution :

We find the LCM of 16,28,40 and 77.

2 | 16  28  40  77

2 | 8   14   20  77

2 | 4   7     10  77

2 | 2   7     5   77

5 | 1    7     5   77

7 | 1    7     1   77

11 | 1    1     1    11

   | 1    1     1     1

LCM(16,28,40,77)=2\times 2\times 2\times 2\times 5\times 7\times 11LCM(16,28,40,77)=2×2×2×2×5×7×11

LCM(16,28,40,77)=6160LCM(16,28,40,77)=6160

In each case it leaves a remainder 5 so we add 5 in the LCM of the numbers.

i.e. 6160+5=6165.

Therefore, The least number which when divided by 16,28,40 and 77 leaves 5 as a remainder in each case is 6165.

Answer 2

Answer:

6168

Step-by-step explanation:

LCM of 16,28,40,77 would be

2x2x2x7x2x1x5x11=6160

(6160+8=6168)

therefore 6168 is the right answer