Question

determine the magnetic field at point(C) in the figure​

Answer 1

Answer:

hope the answer will help you

Answer 2

Answer:

The magnetic field at point(C) is given by$&=\frac{\mu_{0} I}{4 \pi R}\left(\frac{3}{2}+\frac{1}{\pi}\right) \otimes\end{aligned}$

Explanation:

(a)

Magnetic field due to straight wires=0.

Magnetic field due to a semicircular wire

$B_{\text {semicircular }}=\frac{\mu_{0} I}{2 R}\left(\frac{\theta}{2 \pi}\right)=\frac{\mu I}{2 R}\left(\frac{\pi}{2 \pi}\right) ог \\ B_{\text {semicircular }}=\frac{\mu_{0} I}{4 R}$

The direction can be verified from the right hadn rule that will be down ward into the plane of the page.

(b)

Magnetic field due to straight wire 1-2 will be zero. as in its direction is passing through centre of the circular wire. Magnetic field due to circular part

$B_{\text {circular }}=\frac{\mu_{0} I}{2 R}\left(\frac{\theta}{2 \pi}\right)=\frac{\mu_{0} I}{2 R}\left(\frac{(3 / 2) \pi}{2 \pi}\right)$

$B_{\text {circular }}=\frac{3 \mu_{0} I}{8 R} \otimes$

Magnetic field due to semi-infinite wire 3-4,

$B_{\text {straight }}=\frac{\mu_{0} I}{4 \pi R} \otimes$

Net magnetic field at $\mathrm{C}$

$\begin{aligned}B_{0} &=\frac{3 \mu_{0} I}{8 R}+\frac{\mu_{0} I}{4 \pi R} \\B_{0} &=\frac{\mu_{0} I}{4 \pi R}\left(\frac{3}{2}+\frac{1}{\pi}\right) \otimes\end{aligned}$