Question

Determine the magnetic field at the center of the semicircular piece of wire with radius 0.20 m. The current carried by the semicircular piece of wire is 150 A.

Answer 1

Answer:

2.4×10-4 T

Explanation:

The radius of the semicircular piece of wire = 0.20 m

Current carried by the semicircular piece of wire = 150 A

Magnetic field is given as: B=μ0NI2a

The differential form of Biot-Savart law is given as: dB=μ0I4πdIsinθr2 B=μ04πI∫dI×r^r2 =μ04πIr2∫dI =μ04πIr2πr =μ0I4r =4π×10−7T.m/A(150A)4(0.20m)

=2.4×10-4 T

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Answer 2

Explanation:

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