Question

determine the magnetic field intensity due to a current caring conductor of 8A at a distance of 4cm​

Answer 1

Answer:

Correct option is

B

42×10−5 T

This field due to the coil will be in a direction west to east which is perpendicular to the direction of earth's magnetic field. Let east be positive x-direction and north be positive y-axis.

Magnetic field due to a long current carrying conductor is given by the formula,

Bl=2πaμ0I

Bl=2π×(0.04)8×4π×10−7=4×10−5 Ti^

Magnetic field due to earth's horizontal magnetic field is:

Bh=4×10−5Tj^

Hence, resultant magnetic field is:

B=Bl+Bh 

∣B∣=(4×10−5)2+(4×10−5)2=42×10−5 T

Explanation:

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