determine the magnitude and direction of electric field, which would balance the weight of proton, placed in a electric field
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0
Answer:
The force acting on a charged particle in the presence of an electric field is given by:
F
=
q
E
, where:
F is the force
q is the magnitude of the charge
E is the electric field
The force acts in the same direction as that of the electric field, when the charge is positive and the opposite direction when the charge is negative.
Answered by
0
Answer:
To balance proton in electric field:
qE=mg
Or E=mg÷q
=1.7×10^-27×9.8÷1.6×10^-19
=10×10^-8
=1×10^-7 V/M
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