Question

Determine the magnitude of an electric field that will balance the weight of an electron.( mass of electron= 9.1×10-³¹ kg)​

Answer 1

Explanation:

For the equilibrium of electron

mg=eE⇒E=

e

mg

=

1.6×10

−19

9.1×10

−31

×9.8

=5.57×10

−11

N/C