Question

Determine the mass in grams of C atom in 12.74 g urea

Answer 1

Answer:

Molecular formula of urea CON

2

H

2

Molar mass of urea = 60gmol

−1

Number of moles of urea = n=

M

W

=

60

5.6

=0.09333mol

Now,

∴ 1 mol urea contains 4 gram atoms of hydrogen(H)

∴ 0.09333mol urea contains==4×0.09333=0.3733 gram atom of H.

Now,

1gm atom of H contains =6.022×10

23

atoms of H.

0.3733gram atom of hydrogen contains = 6.022×10

23

×0.3733=2.248×10

23

Conclusion: Number of H atoms = 2.248×10

23

Explanation:

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Answer 2

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Molecular formula of urea CON²H²

Molar mass of urea = 60gmol

Number of moles of urea = n= W/

= 5.6/60 = 0.09333 mol

• Now;

1 mol urea contains 4 gram atoms of hydrogen ( H ).

• Therefore; 0.09333mol urea contains = 4×0.09333 = 0.3733 gram atoms of H.

• Now;

1 gram atom of H contains = 6.022×10²³ atoms of H.

0.3733 gram atom of H contains :-

= 6.022×10²³×0.3733

= 2.248 × 10²³

• Conclusion:
• Number of H atoms = 2.248×10²³