Determine the maximum amount of AlCl3 that was produced during the experiment. Explain how you determined this amount.
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0
Answer:
For the maximum value of the Vant Hoff's factor, we take dissociation constant α as 1, because AlCl
3
undergoes 100% dissociation and every AlCl
3
molecule has turned into one Al
3+
ion and three Cl
−
ions i.e. total 4 ions are produced. Hence, the value of the Vant Hoff's factor will be equal to 4.
Answered by
1
Answer:
4 moles of AICI3
Explanation:
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