Question

Determine the maximum bit rate for a channel having bandwidth equal to 1600hz, if s/n ratio is 20dB.​

Answer 1

Answer:

The maximum bit rate for a channel having bandwidth equal to 1600hz, if s/n ratio is 20dB is $R_{max}$ = 20640 bits/sec

Explanation:

From the above question,

They have given :

Bandwidth equal to 1600hz, if s/n ratio is 20dB.​

The maximum bit rate for a channel with a bandwidth of 1600 Hz and a signal-to-noise ratio of 20 dB is 12800 bps (bits per second).

Given B = 1600 Hz

S/N = 20 dB

But 20 dB = 10 log (S/N)

S/N = 100

1600 Hz * log2 (1+20 dB) = 12800 bits/second.

The maximum bit rate for a channel with bandwidth of 1600 Hz and a signal-to-noise ratio of 20 dB is 160 kbps.

The maximum bit rate:

$R_{max}$ = $B$ $log_{2}$ $[ 1 + \frac{S}{N} ]$

        = 1600 $log_{2}$ $[ 1 + 100 ]$

$R_{max}$ = 20640 bits/sec

The maximum bit rate for a channel having bandwidth equal to 1600hz, if s/n ratio is 20dB is $R_{max}$ = 20640 bits/sec

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