Question

Determine the maximum horizontal force P that can be applied to the 12kg hoop without causing it to rotate as shown in Figure. The coefficient of static friction between the hoop and the surfaces at A and B is,$\mu_s=0.2$ Take r = 300mm.

Answer 1

Answer: 240N

Step-by-step explanation:

τ ≤ f (total)

=> F * r⊥ ≤ f(a) + f(b)

=> P* 300 mm ≤ μsN + μsN'

=> 0.3P  ≤  0.2*12*10 + 0.2P)

=> 0.3P  ≤  24 + 0.2P

=.> 0.1P  ≤  24

=> P  ≤  240

Hence, maximum froce is 240N .

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Amrit