Question

Determine the molality of 3000 g of solution containing 37.3 g of KCl (Mol. Wt: 74.55 g/mol)?​

Answer 1

Explanation:

molality = moles of solute

_____________

kg of solvent

moles of solute = 37.3

____

74.55

for solvent,

solution = solute + pure solvent (water)

3000= 37.3 + pure solvent

solvent = 3000-37.3

=2962.7 gm

convert into kg

and then put values into the formula